golf swing

golf tees
goaliejoe asked:


A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 26° above the horizontal. The ball strikes the fairway a horizontal distance of 200 m from the tee. Assume the fairway is level. (a) How high is the rise above the fairway? (b) What is the speed of the ball as it strikes the fairway?

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  • Comments

    Dudley Do Right on 4 September, 2010 at 4:36 am #

    a. 27.8 m

    b. Vx = cos 26 *44 m/s = 39.5 m/s
    Vy = sin 26 *44 m/s - 1/2 g t^2 = 19.3 - 125.5 = - 106.2 m/sec

    V = sqrt (Vx^2 +Vy^2) = 113.3 m/s